Of the metals : $B e, M g, C a$ and $S r$ of group 2 in the periodic table, the least ionic chloride will be formed by:

B e

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C a

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M g

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S r

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Solution

The correct option is A $B e$
Beryllium halides are covalent in nature. This is due to the small size and high charge density of $B e^{2 +}$ ion i.e., it has high polarising power. However, the halides of the other alkaline earth metals (fluorides, chlorides, bromides, and iodides) are ionic solids.

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Similar questions

Of the metals Be , Mg,Ca and Sr of group II A. In the periodic table the least ionic chloride would be formed by

B e^{2 +}

M g^{2 +},

S r^{2 +}

C a^{2 +}

B e, M g, C a, S r, B a

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