Of the three angles of a triangle, one is twice the smallest and another is three times the smallest. Find the angles.

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Solution

Let the smallest angle of the given triangle be $x^{\circ}$ . Then, the other two angles are of 2 $x^{\circ}$ and 3 $x^{\circ}$ .

So, $x^{\circ}$ + 2 $x^{\circ}$ + 3 $x^{\circ}$ = $180^{\circ}$

$x^{\circ}$ = $30^{\circ}$

Hence, the angles of the trinagles are

$30^{\circ}$ , $60^{\circ}$ and $90^{\circ}$ .

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Of the three angles of a triangle, one is twice the smallest and another is three times the smallest. Find the angles.

Let the smallest angle of the given triangle be x∘. Then, the other two angles are of 2x∘ and 3x∘. So, x∘ + 2x∘ + 3x∘ = 180∘ x∘ = 30∘ Hence, the angles of the trinagles are 30∘, 60∘ and 90∘.