Of the three angles of a triangle, one is twice the smallest and another one is thrice the smallest.Find the angles.

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Solution

Let the smallest angle be x
One angle=2x
Another angle =3x

We know that
Sum of all angles in the triangle =180
x+2x+3x=180°
6x=180°
Therefore, x=30°
and the other two angles are: 2x=60°
3x =90°
Therefore, the angles are 30°,60°,90°.

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Of the three angles of a triangle, one is twice the smallest and another one is thrice the smallest.Find the angles.

Let the smallest angle be x One angle=2x Another angle =3x We know that Sum of all angles in the triangle =180 x+2x+3x=180° 6x=180°Therefore, x=30°and the other two angles are: 2x=60° 3x =90°Therefore, the angles are 30°,60°,90°.

Let the smallest angle be x
One angle=2x
Another angle =3x

We know that
Sum of all angles in the triangle =180
x+2x+3x=180°
6x=180°
Therefore, x=30°
and the other two angles are: 2x=60°
3x =90°
Therefore, the angles are 30°,60°,90°.