Question

Of the two supplementary angles the measure of larger angle is ${50}^o$ more than the measure of the angle . find the measure of each angle.

Answer 1

Let the smaller angle be x

Large rangle $=x+50.$

Given sum of supplementary angles is$=180.$

$X+X+50=180$

$2X+50=180.$

$2X=180-50$

$2X=130$

$X=\frac{130}{2}$

$X=65$

Therefore smaller angle$=65.$

Larger angle$=X+50=65+50=110.$