Of two numbers ,3 times the larger one is greater than 4 times the smaller one by 7.Also, the sum of numbers is larger than 6 times their difference by 4.Find the numbers.
Let the greater one be x and smaller one be y. So :-
3x - 4y =7
3x-4y-7=0 .. .....(1)
(x + y) - 6(x - y) = 4
x + y -6x + 6y = 4
-5x + 7y = 4 ....(2)
Now by substitution method :-
From equation (2)
7y = 4+ 5x
y = (4 + 5x) / 7 .... (3)
Now by putting this value of y in equation (1) :-
3x - 4{(4+ 5x) / 7} = 6
21x -16 - 20x = 42
x = 58
Therefore, by putting this value of x in equation (3) , value of y will be ;-
y = {4 + 5(58)} / 7
= (4 + 290) / 7
= 294 / 7
= 42
Coclusion :-
Bigger no. (x) = 58
Smaller no. (y) = 42