$O H^{-}$ is more basic than $S H^{-}$ because

Oxygen is more electronegative than sulphur

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Oxygen is smaller than sulphur

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O and S are different hybridised

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none of the three

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Solution

The correct option is B
Oxygen is smaller than sulphur

Sulphur is larger than oxygen due to which electrons on sulphur are more dispersed and hence lesser available than that on oxygen.

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Similar questions

$O H^{-}$ is more basic than $S H^{-}$ because

Ammonia is more basic than phosphine because

L a (O H)_{3}

L u (O H)_{3}

{C H}_{3} O H

{C H}_{3} S H

C (O H)_{4}

S i (O H)_{4}

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