Oil flow through a 200 mm diameter horizontal cast iron pipe ( friction factor, f = 0.0225 ) of length 500 m. The volumetric flow rate is $0.2 m^{3} / s$ . The head loss ( in m) due to friction is ( assume $g = 9.81 m / s^{2}$ )

116.18

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0.116

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18.22

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232.36

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Solution

The correct option is A 116.18
Given data:
d = 200 mm = 0.2 m

$∴ A = \frac{π}{4} d^{2} = \frac{3.14}{4} \times (0.2)^{2}$

$= 0.0314 m^{2}$
f = 0.0225
L = 500 m
$Q = 0.2 m^{3} / s$
also Q = AV
$∴ 0.2 = 0.0314 \times V$
or V = 6.369 m/s

We know that the Darcy's formula, head loss due to friction,

$h_{f} = \frac{f L V^{2}}{2 g d}$

$= \frac{0.0225 \times 500 \times (6.369)^{2}}{2 \times 9.81 \times 0.2}$

= 116.29 m of oil

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Oil flow through a 200 mm diameter horizontal cast iron pipe ( friction factor, f = 0.0225 ) of length 500 m. The volumetric flow rate is 0.2m3/s. The head loss ( in m) due to friction is ( assume g=9.81 m/s2)

The correct option is A 116.18Given data: d = 200 mm = 0.2 m ∴A=π4d2=3.144×(0.2)2 =0.0314m2 f = 0.0225 L = 500 m Q=0.2m3/s also Q = AV ∴0.2=0.0314×V or V = 6.369 m/s We know that the Darcy's formula, head loss due to friction, hf=fLV22gd =0.0225×500×(6.369)22×9.81×0.2 = 116.29 m of oil

Oil flow through a 200 mm diameter horizontal cast iron pipe ( friction factor, f = 0.0225 ) of length 500 m. The volumetric flow rate is $0.2 m^{3} / s$ . The head loss ( in m) due to friction is ( assume $g = 9.81 m / s^{2}$ )