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Fluid Mechanics

Couette Flow

Oil μ = 0.44 ...

Question

Oil $(μ = 0.44 P a - s, r = 888 k g / m^{3}$ ) is filled in the space between two parallel plates which are 18 mm apart. The upper plate is moving at a velocity of 4 m/s. What is the shear stress on the plate?

97.8 Pa

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48.9 Pa

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79.8 Pa

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87.9 Pa

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Solution

The correct option is A 97.8 Pa
$Shear stress, τ = μ \frac{d u}{d y} = 0.44 \times \frac{4}{0.018}$
$= 97.8 Pa$

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Oil (μ=0.44 Pa−s,r=888kg/m3) is filled in the space between two parallel plates which are 18 mm apart. The upper plate is moving at a velocity of 4 m/s. What is the shear stress on the plate?

The correct option is A 97.8 PaShear stress, τ=μdudy=0.44×40.018 =97.8 Pa

Oil $(μ = 0.44 P a - s, r = 888 k g / m^{3}$ ) is filled in the space between two parallel plates which are 18 mm apart. The upper plate is moving at a velocity of 4 m/s. What is the shear stress on the plate?

The correct option is A 97.8 Pa
$Shear stress, τ = μ \frac{d u}{d y} = 0.44 \times \frac{4}{0.018}$
$= 97.8 Pa$