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Question
On a 120 m track, a train travels the first 30 km at a uniform speed of 30 km/hr.calculate speed with which the train should rest of the track so as to get the average speed of 60 km/hr for the entire trip?
On a 120 m track, a train travels the first 30 km at a uniform speed of 30 km/hr.calculate speed with which the train should rest of the track so as to get the average speed of 60 km/hr for the entire trip?
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Solution
Total distance = 120 km
Average speed =60 kmph
Total time duration = d/v= 120 / 60 = 2 hours
Time taken for the first 30 km = d/v
= 30 km /30 kmph
= 1 hours
Hence, time remaining to cover the remaining 90 km(120-30) = 2 hrs - 1 hrs = 1 hour
Speed during 90 km = d/t
= 90km/1hr = 90kmph
Average speed =60 kmph
Total time duration = d/v= 120 / 60 = 2 hours
Time taken for the first 30 km = d/v
= 30 km /30 kmph
= 1 hours
Hence, time remaining to cover the remaining 90 km(120-30) = 2 hrs - 1 hrs = 1 hour
Speed during 90 km = d/t
= 90km/1hr = 90kmph
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