On a 200 km track,a train travelles first 50 km at a uniform speed of 40 km/h. How fast should it travel the next 150 km to maintain an average speed of 60 km/h for the whole journey
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Solution
First let us find the time taken for the first 50 kms(t1) t1 = distance/speed t1 = 50/40 t1 = 5/4 hrs.
now let us find the time taken for the whole journey(T) T = d/s T = 200/60 T = 20/6 T = 10/3
now let us find the leftover time(t2) t2 = T - t1 t2 = 10/3 - 5/4 (LCM is 12) t2 = (40-15)/12 t2 = 25/12
now with the time and distance let us find the speed. S = d/t S = 150/25/12 S = 150 x 12/25( 25 x 6 =150) S = 6 x 12 S = 72km/hr
checking average speed = total distance/total time Avg. Speed = 200/10/3 Avg. speed = 200 x 3/10 Avg. speed = 20 x 3 Avg. speed = 60km/hr.