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Average Speed

on a 60 M str...

Question

on a 60 M stretch of road cyclist Travels first 20 km at a uniform speed of 20 km per hour .how fast must he travel the remaining distance so that his average speed is 10 km per hour for the entire trip?

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Solution

Dear student,
$A v e r a g e s p e e d = \frac{T o t a l D i s \tan c e}{T o t a l t i m e} S o t o t a l t i m e t a k e n f o r t h e j o u r n e y = \frac{60}{10} = 6 h r s F i r s t 20 K m a r e c o v e r e d a t a s p e e d o f 20 k m / h r, s o t i m e t a k e n i s T i m e = \frac{20}{20} = 1 h r N o w t h e d i s \tan c e l e f t t o b e c o v e r e d = 40 K m T i m e l e f t t o c o v e r t h i s d i s \tan c e = 6 - 1 = 5 h r s S o s p e e d r e q u i r e d t o c o v e r t h i s d i s \tan c e = \frac{40}{5} = 8 k m / h r$

The cyclist should travel the remaining distance at a speed of 8 Km/hr

Regards

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