On a circle of radius 3 cm draw its two chords. Then construct the perpendicular bisector of these chords.
Where do they meet? [4 MARKS]
Construction of circle: 1 Mark
Construction of chords: 1 Mark
Construction of bisector: 1 Mark
Meeting point: 1 Mark
i) Mark any point C on the sheet.Now, by adjusting the compasses up to 3 cm and by putting the pointer of compasses slowly to draw the circle.
It is the required circle of 3 cm radius.
ii) Take any two chords AB and CD in the circle.
iii) Taking A and B as centres and with radius more than half of AB, draw arcs on both sides of AB, intersecting
each other at E, F. Join EF which is the perpendicular bisector of AB.
iv) Taking C and D as centres and with radius more than half of CD, draw arcs on both sides of CD, intersecting
each other at G and H . Join GH which is the perpendicular bisector of CD.
Now, we find that extended EF and GH meet at the centre of circle O.