On a circlular area ${2 c m}^{2}$ , a person applies a force of $20 N$ . is the pressure on that area.

10^{3} P a

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10^{2} P a

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10^{5} P a

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10^{7} P a

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Solution

The correct option is C $10^{5} P a$
The area on which the pressure is calculated is ${2 c m}^{2}$ , and the force applied is $20 N$ .

Pressure = $\frac{F o r c e}{A r e a}$ = $\frac{20 N}{2 \times 10^{- 4} m^{2}}$
[ $∵ 1 c m^{2} = 10^{- 4} m^{2}$ ]
= $10^{5} \frac{N}{m^{2}}$ = $10^{5} P a$

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On a circlular area 2 cm2, a person applies a force of 20 N. is the pressure on that area.

The correct option is C 105 PaThe area on which the pressure is calculated is 2 cm2, and the force applied is 20 N. Pressure = ForceArea = 20 N2×10−4 m2 [∵1 cm2=10−4 m2] = 105 Nm2 = 105 Pa

On a circlular area ${2 c m}^{2}$ , a person applies a force of $20 N$ . is the pressure on that area.

The correct option is C $10^{5} P a$
The area on which the pressure is calculated is ${2 c m}^{2}$ , and the force applied is $20 N$ .

Pressure = $\frac{F o r c e}{A r e a}$ = $\frac{20 N}{2 \times 10^{- 4} m^{2}}$
[ $∵ 1 c m^{2} = 10^{- 4} m^{2}$ ]
= $10^{5} \frac{N}{m^{2}}$ = $10^{5} P a$