On a common hypotenuse AB, two right triangles ACB and ADB are situated on opposite sides, Prove that ∠BAC=∠BDC.
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Solution
Given , ACB and ADB are two right triangles To Prove, <BAC=<BDC <Proof, <C + <D = 90° + 90° = 180° Therefore ADBC is a Cyclic Quadrilateral <BAC and <BDC are made by the same arc BC Therefore, <BAC=<BDC Hence Proved