On a day when temperature reaches 68- F- What is the absolute temperature-A- 20B- 293C- 341D- 32

The correct option is B 293F 32/9 = C/5 68 32/9 = C/5 C/5 = 36/9 = 4 C = 20 T = 273 + 20 = 293 K ...

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Standard XII

Chemistry

Units and Dimensions

On a day when...

Question

On a day when temperature reaches $68^{\circ} F,$ What is the absolute temperature?

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293

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341

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Solution

The correct option is B 293
$\frac{F - 32}{9} = \frac{C}{5} \frac{68 - 32}{9} = \frac{C}{5} \frac{C}{5} = \frac{36}{9} = 4 C = 20 T = 273 + 20 = 293 K$

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On a day when temperature reaches 68 ∘F, What is the absolute temperature?

The correct option is B 293F−329=C568−329=C5C5=369=4C=20T=273+20=293 K

On a day when temperature reaches $68^{\circ} F,$ What is the absolute temperature?

The correct option is B 293
$\frac{F - 32}{9} = \frac{C}{5} \frac{68 - 32}{9} = \frac{C}{5} \frac{C}{5} = \frac{36}{9} = 4 C = 20 T = 273 + 20 = 293 K$