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Interference in Sound Waves

On a day when...

Question

On a day when the speed of sound is 345 m/s, the fundamental frequency of a closed organ pipe is 220 Hz. The length of this closed pipe is $392 \times 10^{- x} m$ . Find the value of x.

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Solution

Given- $f_{1} = 220, v = 345 m / s$
Fundamental frequency of a closed organ pipe is given by ,
$f_{1} = v / 4 l$ ,
or $l = v / 4 f_{1} = 345 / (4 \times 220) = 0.392 m$

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