On a glass plate a light wave is incident at an angle of $60^{\circ}$ . If the reflected and the refracted waves are mutually perpendicular, the refractive index of material is

$\frac{\sqrt{3}}{2}$

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$\sqrt{3}$

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$\frac{3}{2}$

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$\frac{1}{\sqrt{3}}$

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Solution

The correct option is B
$\sqrt{3}$

Refractive index of a medium, $μ = \frac{s i n i}{s i n r}$ (From snell's Law)
In the figure given below,

$∠ i = 60^{\circ}, ∠ r = 30^{\circ}$
so $μ = \frac{s i n 60}{s i n 30} = \sqrt{3}$

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On a glass plate a light wave is incident at an angle of 60∘. If the reflected and the refracted waves are mutually perpendicular, the refractive index of material is

The correct option is B √3 Refractive index of a medium,μ=sinisinr(From snell's Law) In the figure given below, ∠i=60∘,∠r=30∘ so μ=sin60sin30=√3

On a glass plate a light wave is incident at an angle of $60^{\circ}$ . If the reflected and the refracted waves are mutually perpendicular, the refractive index of material is

The correct option is B
$\sqrt{3}$

Refractive index of a medium, $μ = \frac{s i n i}{s i n r}$ (From snell's Law)
In the figure given below,

$∠ i = 60^{\circ}, ∠ r = 30^{\circ}$
so $μ = \frac{s i n 60}{s i n 30} = \sqrt{3}$