On a glass plate a light wave is incident at an angle of $60^{o}$ . If the reflected and the refracted waves are mutually perpendicular, the refractive index of material is

\frac{\sqrt{3}}{2}

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\sqrt{3}

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\frac{3}{2}

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\frac{1}{\sqrt{3}}

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Solution

The correct option is B $\sqrt{3}$
From figure
$< i = 60^{o}, < r = 30^{o}$
so $μ = \frac{sin 60}{sin 30} = \sqrt{3}$

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On a glass plate a light wave is incident at an angle of 60o. If the reflected and the refracted waves are mutually perpendicular, the refractive index of material is

The correct option is B √3From figure<i=60o,<r=30oso μ=sin60sin30=√3

On a glass plate a light wave is incident at an angle of $60^{o}$ . If the reflected and the refracted waves are mutually perpendicular, the refractive index of material is

The correct option is B $\sqrt{3}$
From figure
$< i = 60^{o}, < r = 30^{o}$
so $μ = \frac{sin 60}{sin 30} = \sqrt{3}$