On a graph paper plot the points A(-4,2), B(2,-6) and C(1,7). Then the point of intersection of the locus of a point equidistant from B and C and the locus of a point equidistant from A and C lies in the fourth quadrant.
On a graph paper plot the points A(-4,2), B(2,-6) and C(1,7). Then the point of intersection of the locus of a point equidistant from B and C and the locus of a point equidistant from A and C lies in the fourth quadrant.
The correct option is B False
Plot the points A(-4,2), B(2,-6) and C(1,7) on a graph paper.
We know that the locus of a point which is equidistant from two fixed points is the perpendicular bisector of the line segment joining the two fixed points.
Hence to find the locus of a point equidistant from B and C and the locus of a point equidistant from A and C, we draw perpendicular bisectors 'l' and 'm' of BC and AC respectively, a shown above.
From these constructions, we note that the lines 'l' and 'm' intersect at a point(P, in the graph) which lies in the first quadrant.
False
Plot the points A(-4,2), B(2,-6) and C(1,7) on a graph paper.
We know that the locus of a point which is equidistant from two fixed points is the perpendicular bisector of the line segment joining the two fixed points.
Hence to find the locus of a point equidistant from B and C and the locus of a point equidistant from A and C, we draw perpendicular bisectors 'l' and 'm' of BC and AC respectively, a shown above.
From these constructions, we note that the lines 'l' and 'm' intersect at a point(P, in the graph) which lies in the first quadrant.
