On a hill, the temperature at $8 p . m$ . was $2^{0} C$ but at the midnight of the same day, it fell down to $- 3^{0} C$ . By how many degees did the temperature fall?

$6^{0} C$

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$5^{0} C$

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$2^{0} C$

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$3^{0} C$

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Solution

The correct option is B
$5^{0} C$

Given,
Temperature at $8 p . m$ $= 2^{0} C$
Temperature at midnight $= - 3^{0} C$
∴ Decrease in temperature $= 2 - (- 3) = 2 + 3 = 5^{0} C$
Hence, the correct option is B.

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Similar questions

On a particular day, the temperature of Delhi at $10$ am was $13^{0} C$ but by the midnight, it fell down to $6^{0} C$ . The same day the temperature in Chennai at $10$ am was $18^{0} C$ but fell down to $10^{0} C$ by the midnight. Which fall is greater?

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On a hill, the temperature at 8p.m. was 20C but at the midnight of the same day, it fell down to -30C. By how many degees did the temperature fall?

The correct option is B 50CGiven,Temperature at 8p.m =20CTemperature at midnight =-30C∴ Decrease in temperature=2-(-3)=2+3=50CHence, the correct option is B.

On a hill, the temperature at $8 p . m$ . was $2^{0} C$ but at the midnight of the same day, it fell down to $- 3^{0} C$ . By how many degees did the temperature fall?

The correct option is B
$5^{0} C$

Given,
Temperature at $8 p . m$ $= 2^{0} C$
Temperature at midnight $= - 3^{0} C$
∴ Decrease in temperature $= 2 - (- 3) = 2 + 3 = 5^{0} C$
Hence, the correct option is B.