On a hill, the temperature at $8$ p.m. was $2^{o}$ C but at the mid-night of the same day, it fell down to $- 3^{o}$ C. By how many degrees did the temperature fall?

6^{o}

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5^{o}

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2^{o}

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3^{o}

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Solution

The correct option is D $5^{o}$ C
Temperature difference $\to$ Temperature at midnight $-$ Temperature at 8p.m.
Temperature difference $\to$ ( $- 3$ ) $-$ ( $2$ ) $\to$ $- 5$
Temperature fall by 5 degree.
Hemce Option B is correct.

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