Question

On a large tray of mass M, an ice cube of mass m, edge L is kept. If the ice melts completely, the centre of mass of the system comes down by

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

After melting of ice, the centre of mass of ice and tray coincides.

$\therefore$ Centre of mass comes down by $△x_{cm}=\frac{M\left(0\right)+m\frac{L}{2}}{M+m}$

=$\frac{mL}{2(M+m)}$