On a large tray of mass M, an ice cube of mass m, edge L is kept. If the ice melts completely, the centre of mass of the system comes down by

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Solution

The correct option is A

After melting of ice, the centre of mass of ice and tray coincides.

$∴$ Centre of mass comes down by $△ x_{c m} = \frac{M (0) + m \frac{L}{2}}{M + m}$

= $\frac{m L}{2 (M + m)}$

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On a large tray of mass M, an ice cube of mass m, edge L is kept. If the ice melts completely, the centre of mass of the system comes down by

The correct option is A After melting of ice, the centre of mass of ice and tray coincides. ∴ Centre of mass comes down by △xcm=M(0)+mL2M+m =mL2(M+m)

The correct option is A

After melting of ice, the centre of mass of ice and tray coincides.

$∴$ Centre of mass comes down by $△ x_{c m} = \frac{M (0) + m \frac{L}{2}}{M + m}$

= $\frac{m L}{2 (M + m)}$