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Question

On a large tray of mass M, an ice cube of mass m, edge L is kept. If the ice melts completely, the center of mass of the system comes down by:

A
mL2(M+m)
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B
(Mm)L2(M+m)
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C
(M+2m)L2(M+m)
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D
2ML2(M+m)
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Solution

The correct option is A mL2(M+m)
It is a large tray,so when ice melts the level of water is negligible.
Shift in COM is basically the level of COM before melting
ycm before melting
=m×L2(m+m)
mL2(m+m)

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