On a morning walk, three persons step off together and their steps measure 45 cm, 60 cm and 65 cm respectively. Then, the minimum distance each should walk so that each can cover the same distance in complete steps
A
2240 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2340 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2780 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2840 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 2340 cm The three persons start walking together.
∴ Minimum distance covered by each of them in complete steps
= LCM of the measures of their steps
= LCM (45, 60, 65)
Now, 45=3×3×5=32×5
65=5×13=5×13
⇒LCM(45,60,65)=22×32×5×13=2340
Thus, each person should walk a minimum of 2340 cm in complete steps.