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Question
On a morning walk, three persons step out together and their steps measure 30 cm, 36 cm and 40 cm respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps?
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Solution
It is given that, three persons step out together and their steps measure 30 cm, 36 cm and 40 cm respectively.
The minimum distance each should walk so that each can cover the same distance in complete steps is the LCM of 30, 36 and 40.
30 = 2 × 3 × 5
36 = 2 × 2 × 3 × 3
40 = 2 × 2 × 2 × 5
Therefore, LCM of 30, 36 and 40 is 2 × 2 × 2 × 3 × 3 × 5 = 360
Hence, the minimum distance each should walk so that each can cover the same distance in complete steps is 360 cm.
The minimum distance each should walk so that each can cover the same distance in complete steps is the LCM of 30, 36 and 40.
30 = 2 × 3 × 5
36 = 2 × 2 × 3 × 3
40 = 2 × 2 × 2 × 5
Therefore, LCM of 30, 36 and 40 is 2 × 2 × 2 × 3 × 3 × 5 = 360
Hence, the minimum distance each should walk so that each can cover the same distance in complete steps is 360 cm.
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