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Question

On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are 42W and 242 W respectively. What will be the temperature on the new scale, corresponding to the temperature of 42C on the Celsius scale ?

A
200W
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B
142W
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C
84W
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D
126W
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Solution

The correct option is D 126W
We know,
(xLFP)(UFPLFP)= constant for every scale.
On Celsius scale,
4201000= constant
On W scale,
W4224242= constant
4201000=W4224242
W=42×200100+42=126W

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