On a particle moving on a circular path with a constant speed v, light is thrown from a projector placed at the centre of the circular path. The shadow of the particle is formed on the wall. The velocity of shadow up the wall is

$v s e c^{2} ϕ$

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$v c o s^{2} ϕ$

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$v c o s ϕ$

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None of these

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Solution

The correct option is A
$v s e c^{2} ϕ$

$\frac{v^{'} c o s ϕ}{R s e c ϕ} = \frac{v}{R} v^{'} = v s e c^{2} ϕ$

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On a particle moving on a circular path with a constant speed v, light is thrown from a projector placed at the centre of the circular path. The shadow of the particle is formed on the wall. The velocity of shadow up the wall is

The correct option is A v sec2ϕ v′cos ϕR sec ϕ=vRv′=vsec2ϕ

The correct option is A
$v s e c^{2} ϕ$

$\frac{v^{'} c o s ϕ}{R s e c ϕ} = \frac{v}{R} v^{'} = v s e c^{2} ϕ$