On a particular crossing, out of 100 people, 9 people jumped traffic lights. Find the probability of people not jumping traffic lights.

9/50

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91/100

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9/10

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9/100

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Solution

The correct option is B
91/100

Total possible outcomes = n(S) = 100

The number of people who have not jumped traffic lights = 100 – 9 = 91

P(people not jumping traffic lights) = $\frac{91}{100}$

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On a particular crossing, out of 100 people, 9 people jumped traffic lights. Find the probability of people not jumping traffic lights.

The correct option is B 91/100 Total possible outcomes = n(S) = 100 The number of people who have not jumped traffic lights = 100 – 9 = 91 P(people not jumping traffic lights) = 91100

The correct option is B
91/100

Total possible outcomes = n(S) = 100

The number of people who have not jumped traffic lights = 100 – 9 = 91

P(people not jumping traffic lights) = $\frac{91}{100}$