Question

On a particular day, at a crossing in a city, the various types of 240 vehicles going past during a time interval were observed as under:

$\begin{array}{cccc}\text{Type of vehicle}& \text{Two-wheelers}& \text{Three-wheelers}& \text{Four-wheelers}\\ \text{Frequency}& 84& 68& 88\end{array}$

Out of these vehicles, one is chosen at random. What is the probability that the chosen vehicle is a two-wheeler?

Answer 1

ANSWER:
Total number of vehicles going past the crossing = 240
Number of two-wheelers = 84
Let E be the event that the selected vehicle is a two-wheeler. Then,

required probability = P(E) = $\frac{84}{240}=0.35$