Question

On a rough horizontal surface, a body of mass 2 kg is given a velocity of 10 m/s. If the coefficient of friction is 0.2 and g=10 $m/s^2$, the body will stop after covering a distance of

• A. 10 m
• B. 25 m
• C. 50 m
• D. 250 m

Answer 1

The correct option is B

25 m

$S=\frac{u^2}{2\mu g}=\frac{(10{)}^2}{2\times 0.2\times 10}=25m$