Volume of the balloon
Given: V1=2 L,T1=23.4∘C=296.4 K
and T2=26.1∘C=299.1 K
From Charles law, V∝T
So, V1T1= V2T2⇒ V2= V1T2T1⇒ V2= 2L×299.1 K296.4 K = 2L×1.009 = 2.018 L
Final answer: Volume of the balloon when the ship reaches Indian ocean is 2.018 L