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Standard XII

Chemistry

Charles' Law

On a ship sai...

Question

On a ship sailing in pacific ocean where temperature is 23.4° C, a balloon is filled with 2 L air. What will be the volume of the balloon when the ship reaches the Indian ocean, where temperature is 26.1°C?

1.98 L

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2.02 L

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2.18 L

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5.12 L

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Solution

The correct option is B
2.02 L

Explanation for correct option:
T₁ = (23.4 + 273) = 296.4 K T₂ = 26.1 + 273K = 299.1 K
V₁ = 2 L V₂ = ?
According to Charle’s law,
$\frac{V_{1}}{T_{1}}$ = $\frac{V_{2}}{T_{2}}$
V₂ = $\frac{V_{1} T_{2}}{T_{1}}$
V₂ = $\frac{2 L \times 299.1 K}{296.4 K}$
= 2 L x 1.009
= 2.018 L.
Hence, The correct option is (b)

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On a ship sailing in pacific ocean where temperature is 23.4° C, a balloon is filled with 2 L air. What will be the volume of the balloon when the ship reaches the Indian ocean, where temperature is 26.1°C?

The correct option is B 2.02 LExplanation for correct option:T1 = (23.4 + 273) = 296.4 K T2 = 26.1 + 273K = 299.1 KV1 = 2 L V2 = ?According to Charle’s law,V1T1= V2T2V2 = V1T2T1V2 = 2L×299.1K296.4K = 2 L x 1.009 = 2.018 L.Hence, The correct option is (b)