On a ship sailing in the Pacific ocean, where the temperature is 23.4 $^{\circ}$ C, a balloon is filled with 2 L air. What will be the volume of the balloon when the ship reaches the Indian ocean where the temperature is 26.1 $^{\circ}$ C?

2.0184 L

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1.96 L

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1.88L

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2.42 L

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Solution

The correct option is A
2.0184 L

According to Charles' law

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

$V_{1} = 2 L$ , $V_{2}$ = ?

$T_{1}$ = 273 + 23.4 = 296.4K
$T_{2}$ = 273 + 26.1 = 299.1K

Therefore, $V_{2} = \frac{V_{1} \times T_{2}}{T_{1}}$

$= \frac{2 \times 299.1}{296.4}$

= 2.0182 L

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On a ship sailing in the Pacific ocean, where the temperature is 27 $^{\circ}$ C, a balloon is filled with 2 L air. What will be the volume of the balloon when the ship reaches the Indian ocean where the temperature is 29 $^{\circ}$ C ?

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On a ship sailing in pacific ocean where temperature is 23.4, a balloon is filled with 2L air. What will be the volume of the balloon when the ship reaches Indian ocean, Where temperature is 26.1?

On a ship sailing in the Pacific ocean, where the temperature is 23.4 $^{\circ}$ C, a balloon is filled with 2 L air. What will be the volume of the balloon when the ship reaches the Indian ocean where the temperature is 26.1 $^{\circ}$ C ?

Q. On a ship sailing in the Pacific ocean, where the temperature is

{23.4}^{\circ} C

, a balloon is filled with

2 L

of air. What will be the volume of the balloon when the ship reaches the Indian ocean, where the temperature is

{26.1}^{\circ} C

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On a ship sailing in the Pacific ocean, where the temperature is 23.4∘C, a balloon is filled with 2 L air. What will be the volume of the balloon when the ship reaches the Indian ocean where the temperature is 26.1∘ C?

The correct option is A 2.0184 L According to Charles' law V1T1=V2T2 V1=2L, V2 = ? T1 = 273 + 23.4 = 296.4K T2 = 273 + 26.1 = 299.1K Therefore, V2=V1×T2T1 =2×299.1296.4 = 2.0182 L

On a ship sailing in the Pacific ocean, where the temperature is 23.4 $^{\circ}$ C, a balloon is filled with 2 L air. What will be the volume of the balloon when the ship reaches the Indian ocean where the temperature is 26.1 $^{\circ}$ C?

The correct option is A
2.0184 L

According to Charles' law

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

$V_{1} = 2 L$ , $V_{2}$ = ?

$T_{1}$ = 273 + 23.4 = 296.4K
$T_{2}$ = 273 + 26.1 = 299.1K

Therefore, $V_{2} = \frac{V_{1} \times T_{2}}{T_{1}}$

$= \frac{2 \times 299.1}{296.4}$

= 2.0182 L