On a square handkerchief, nine circular designs each of radius 7 cm are made. Find the area of the remaining portion of the handkerchief.

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Solution

Side of square $= 3 \times$ diameter of $1$ circle
$= 3 \times 14 = 42 c m$

Area of remaining portion $=$ Area of square - $9$ $\times$ area of $1$ circle

$=$ ( $42 \times 42$ ) - $9 \times \frac{22}{7} \times 7 \times 7$

$= 1764 - 1386$

$= 378 {c m}^{2}$

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On a square handkerchief, nine circular designs each of radius 7 cm are made. Find the area of the remaining portion of the handkerchief.

Side of square =3× diameter of 1 circle =3×14=42cmArea of remaining portion = Area of square - 9 × area of 1 circle = (42×42) - 9×227×7×7 =1764−1386 =378cm2

Side of square $= 3 \times$ diameter of $1$ circle
$= 3 \times 14 = 42 c m$

Area of remaining portion $=$ Area of square - $9$ $\times$ area of $1$ circle

$=$ ( $42 \times 42$ ) - $9 \times \frac{22}{7} \times 7 \times 7$

$= 1764 - 1386$

$= 378 {c m}^{2}$