Question

On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in $c{m}^2$. $Take(\pi =\frac{22}{7})$

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• A. 1423
• B. $1432c{m}^2$
• C. $1322c{m}^2$
• D. $1421c{m}^2$

Answer 1

The correct option is A

1423

Area of square Handkerchief $={50}^2=2500c{m}^2$

Total area of circles $=7\times pi\times 7^2=1078c{m}^2$

Remaining area $=2500-1078=1422c{m}^2$ ~ $1422c{m}^2$