On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in $c m^{2}$ .

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Solution

Area of square Handkerchief = $50^{2}$ = 2500 $c m^{2}$

Total area of circles = 7 x $π$ x $7^{2}$ = 1077.02 $c m^{2}$

Remaining area = 2500 - 1077.02 = 1422.98 $c m^{2}$ ~ 1423 $c m^{2}$

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On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in cm2. __

Area of square Handkerchief = 502 = 2500 cm2 Total area of circles = 7 x π x 72 = 1077.02 cm2 Remaining area = 2500 - 1077.02 = 1422.98 cm2 ~ 1423 cm2

On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in $c m^{2}$ .

__

Area of square Handkerchief = $50^{2}$ = 2500 $c m^{2}$

Total area of circles = 7 x $π$ x $7^{2}$ = 1077.02 $c m^{2}$

Remaining area = 2500 - 1077.02 = 1422.98 $c m^{2}$ ~ 1423 $c m^{2}$