On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in $c m^{2}$ .

1423

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1452.6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1466

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1308.6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
1423

Area of square Handkerchief = $50^{2}$ = 2500 $c m^{2}$

Total area of circles = 7 x $π$ x $7^{2}$ = 1078 $c m^{2}$

Remaining area = 2500 - 1078 = 1422 $c m^{2}$

Suggest Corrections

Similar questions

On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in $c m^{2}$ .

On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in $c m^{2}$ . $T a k e (π = \frac{22}{7})$

On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in $c m^{2}$ .

Q. On a square handkerchief, nine circular designs each of radius

7 c m

are made (see figure). Find the area of the remaining portion of the handkerchief.

Q. On a square handkerchief, nine circular designs each of radius

7 c m

are made (see the given figure). Find the area of remaining portion of the handkerchief.

[U s e π = \frac{22}{7}]

Join BYJU'S Learning Program

On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in cm2.

The correct option is A 1423 Area of square Handkerchief = 502 = 2500 cm2 Total area of circles = 7 x π x 72 = 1078 cm2 Remaining area = 2500 - 1078 = 1422 cm2

On a square handkerchief of side 50 cm, seven non-intersecting circles designs of each radius 7 cm are made. Find the area of the remaining portion of the handkerchief in $c m^{2}$ .

The correct option is A
1423

Area of square Handkerchief = $50^{2}$ = 2500 $c m^{2}$

Total area of circles = 7 x $π$ x $7^{2}$ = 1078 $c m^{2}$

Remaining area = 2500 - 1078 = 1422 $c m^{2}$