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Question

On a station 'O', three horizontal angles were measure closing the horizon which are

A=341020′′±3′′

B=1764032′′±4′′

C=14994′′±5′′

Then the correct value of angle A is

A
341020.52′′
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B
341020.82′′
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C
341020.62′′
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D
341020.72′′
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Solution

The correct option is D 341020.72′′
Sum of angles A, B and C

i.e.A+B+C=3595956′′

Error = M.V - TV = 3595956′′3600000′′=004′′

Correction = + 4''

Let us assume C1,C2,C3 are correction in A,BandC

C1+C2+C3=4"...(i)

C1:C2:C3=32:42:52

C1C2=916C1C3=925

From equation (i), C1+169C1+259C1=4′′C1=0.72′′

Corrected angle A=341020.72′′

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