On a symmetrical die the numbers 1, -1, 2, -2, 3 and 0 are marked on its 6 faces. If such a die is thrown 3 times, the probability that the sum of points on them is 6 is

\frac{5}{27}

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\frac{5}{54}

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\frac{5}{108}

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\frac{3}{108}

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Solution

The correct option is C $\frac{5}{108}$
The sum of points on them is 6
(1,2,3) in 6 ways, (0.3,3) in 3 ways and (2,2,2) in 1 way, total 10 ways
Total ways on throwing the dice is 216
Probability $= \frac{10}{216} = \frac{5}{108}$

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On a symmetrical die the numbers 1, -1, 2, -2, 3 and 0 are marked on its 6 faces. If such a die is thrown 3 times, the probability that the sum of points on them is 6 is

The correct option is C 5108The sum of points on them is 6 (1,2,3) in 6 ways, (0.3,3) in 3 ways and (2,2,2) in 1 way, total 10 ways Total ways on throwing the dice is 216Probability =10216=5108

The correct option is C $\frac{5}{108}$
The sum of points on them is 6
(1,2,3) in 6 ways, (0.3,3) in 3 ways and (2,2,2) in 1 way, total 10 ways
Total ways on throwing the dice is 216
Probability $= \frac{10}{216} = \frac{5}{108}$