On a thermometer, the freezing point of water is marked as 20∘C and the boiling point of water is marked as 150∘C . A temperature of 60∘C will be read on this thermometer as ________ ∘C.
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Solution
We know that Tt−T0T100−T0=Tc−0100−0
Given: T100=1500C,T0=200C TC=60∘C
Let Tt be temperature on this new thermometer corresponding to 60∘C on Celsius scale