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Question

On acidification of aqueous borax solution, it gives white flakes. This is due to formation of

A
B(OH)3
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B
B2O3
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C
B2H6
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D
NaBO2
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Solution

The correct option is A B(OH)3
Borax dissolve in water to give both B(OH)3 and [(B(OH)4]. This solution contains equal amounts of weak acid and its salt, thus it can act as a buffer.
On acidification of this solution, [(B(OH)4] reaction with H+ ions to form orthoboric acid. [B4O5(OH)4]2+5H2O2B(OH)3(weak acid)+2[B(OH)4]salt
2[B(OH)4]+2H3O+2B(OH)3+4H2O

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