On acidification of aqueous borax solution, it gives white flakes. This is due to formation of
A
B(OH)3
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B
B2O3
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C
B2H6
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D
NaBO2
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Solution
The correct option is AB(OH)3 Borax dissolve in water to give both B(OH)3 and [(B(OH)4]−. This solution contains equal amounts of weak acid and its salt, thus it can act as a buffer. On acidification of this solution, [(B(OH)4]− reaction with H+ ions to form orthoboric acid. [B4O5(OH)4]2−+5H2O⇌2B(OH)3(weakacid)+2[B(OH)4]−salt 2[B(OH)4]−+2H3O+→2B(OH)3+4H2O