On addition of $1 m l$ solution of $10$ $N a C I$ to $10 m L$ gold sol in the presence of $0.025 g m$ of starch the coagulation is just prevented. Strach has the following gold number:

0.025

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0.25

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2.5

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25

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Solution

The correct option is B $2.5$
Amount of starch added to 10 mL of gold sol required to prevent coagulation of 1 mL of 10% Nacl solution = 0.025 g = 25 mg
Starch required to be added to 10 mL to gold sol to completely . Prevent coagulation by 1 mL of 10% NaCl solution .
$= \frac{25}{100} \times 10 = 2.5 m g$
Therefore , Gold number of starch = 2.5

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On addition of 1ml solution of 10 NaCI to 10mL gold sol in the presence of 0.025gm of starch the coagulation is just prevented. Strach has the following gold number:

On addition of $1 m l$ solution of $10$ $N a C I$ to $10 m L$ gold sol in the presence of $0.025 g m$ of starch the coagulation is just prevented. Strach has the following gold number: