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Normality

On addition o...

Question

On addition of $A g N O_{3}$ slowly to $0.1$ M each of $N a C l$ and $N a B r$ in a solution, what percentage of $B r^{-}$ ions get precipitated when $C l^{-}$ ion starts precipitating ?
$K_{S P} (A g C l) = 1.0 \times 10^{- 10}$ $K_{S P} (A g B r) = 1 \times 10^{- 13}$

A

0.11

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B

99.9

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C

0.01

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D

9.99

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Solution

The correct option is B $99.9$
For precipitation of $A g C l$ ,
$[A g^{+}] required = \frac{K_{S P} (A g C l)}{[C l^{-}]} = \frac{1.0 \times 10^{- 10}}{0.1} = 1.0 \times 10^{- 9} M$
$[B r^{-}] left = \frac{K_{S P} (A g B r)}{[A g^{+}]} = \frac{1.0 \times 10^{- 13}}{1.0 \times 10^{- 9}} = 1.0 \times 10^{- 4} M$
$%$ of remaining, $[B r^{-}] = \frac{1.0 \times 10^{- 4}}{0.1} \times 100 = 0.1$
$%$ of $[B r^{-}]$ which get precipitated $= 100 - 0.1 = 99.9$

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Similar questions

Q. A solution of

0.1 M

{C l}^{-}

0.1 M

{B r}^{-}

0.1 M

I^{-}

A g {N O}_{3}

is gradually added to this solution. Assuming that the addition of

A g {N O}_{3}

does not change the volume.
Given:

K_{s p} (A g C l) = 1.7 \times 10^{- 10}

K_{s p} (A g B r) = 5 \times 10^{- 13}

K_{s p} (A g I) = 8.5 \times 10^{- 17}

What will be the conc. of both ions when the third ion start precipitating.

Q. A solution is

0.1 M

K C l, K B r

K_{2} C r O_{4}

. To this solution solid

A g N O_{3}

is gradually added. Assume no change in the volume of the solution.
Given:

K_{s p} (A g C l) = 1.7 \times 10^{- 10}

K_{s p} (A g B r) = 5 \times 10^{- 13}

K_{s p} (A g_{2} C r O_{4}) = 1.9 \times 10^{- 12}

The concentration of first ion when the second ion starts precipitating is:

Q. The concentration of a solution is

10^{- 4} M

C l^{-}, 10^{- 5} M

B r^{-}

10^{- 3} M

I^{-} .

A g N O_{3} (s)

is added slowly to the solution. The minimum concentration of

A g^{+}

required to start precipitation of all three ions is:
[Given,

K_{s p (A g C l)} = 10^{- 10}, K_{s p (A g B r)} = 10^{- 13}, K_{s p (A g I)} = 10^{- 17}

]

A g N O_{3}

is slowly added to a solution that is

0.001

N a C l, N a B r

N a I

(A) The concentration of

A g^{+}

required to initiate precipitation of each of

A g I, A g B r

A g C l

1.5 \times 10^{- 13}

3.3 \times 10^{- 10}

1.6 \times 10^{- 7}

(B) The percentage of

I^{-}

precipitated before

A g B r

precipitates is

99.95

(C) The percentage of

I^{-}

precipitated before

C l^{-}

precipitates is

99.999917

(K_{s p} (A g I) = 1.5 \times 10^{- 16},

K_{s p} (A g B r) = 3.3 \times 10^{- 13},

K_{s p} (A g C l) = 1.8 \times 10^{- 10})

Which of the above-given option(s) is/are correct?

Q. A solution contains

0.1 M

{C l}^{-}

0.001 M

C r O_{4}^{2 -}

A g {N O}_{3}

is gradually added to this solution, which will precipitate first,

A g C l

{A g}_{2} C r O_{4}

? Assume that the addition causes no change in volume. Given

K_{s p} A g C l = 1.7 \times 10^{- 10} M^{2}

K_{s p} {A g}_{2} C r O_{4} = 1.79 \times 10^{- 12} M^{3}

What percent of

{C l}^{-}

remains in the solution when

C r O_{4}^{2 -}

starts precipitating?

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