Question

On analysis, a substamnce was found to contain;
C = 54. 54% H= 9.09 % O = 36.36 %
The vapour density fo the substance is 44, calculate:
(a) its empirical formula, (b) its molecular formula.

Answer 1

element	%	At.mass	Atomic ratio	simple ratio
C	54.54	12	$\frac{54.54}{12}=4.55$	2
H	9.09	1	$\frac{9.09}{1}=9.09$	4
O	36.36	16	$\frac{36.36}{16}=2.27$	1

(a)So, its empirical formula =
(b)emperical formula mass =44
since vapour density =44
So, molecular mass =2 $\times$ VD=88
or n=2
so molecular formula =