On any given three days, a rickshaw puller earns ₹ $93.50$ , ₹ $68.50$ and ₹ $82.50$ . Find his total earning in these three days.

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Solution

Addition of decimals
Earning on the first day $=$ ₹ $93.50$
Earning on the second day $=$ ₹ $68.50$
Earning on the third day $=$ ₹ $82.50$
Then, total earnings in three days $=$ ₹ $(93.50 + 68.50 + 82.50)$
$=$ ₹ $244.50$
Hence, the total earning in three days ₹ $244.50$ .

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On any given three days, a rickshaw puller earns ₹ 93.50, ₹ 68.50 and ₹ 82.50. Find his total earning in these three days.

Addition of decimalsEarning on the first day =₹ 93.50Earning on the second day =₹ 68.50Earning on the third day =₹ 82.50Then, total earnings in three days =₹ (93.50+68.50+82.50) =₹ 244.50Hence, the total earning in three days ₹ 244.50.

On any given three days, a rickshaw puller earns ₹ $93.50$ , ₹ $68.50$ and ₹ $82.50$ . Find his total earning in these three days.

Addition of decimals
Earning on the first day $=$ ₹ $93.50$
Earning on the second day $=$ ₹ $68.50$
Earning on the third day $=$ ₹ $82.50$
Then, total earnings in three days $=$ ₹ $(93.50 + 68.50 + 82.50)$
$=$ ₹ $244.50$
Hence, the total earning in three days ₹ $244.50$ .