Question

On arranging the following fractions $\frac{4}{9},\frac{7}{9},\frac{1}{9},\frac{3}{9}$ in ascending order we get:

• A. $\frac{4}{9}<\frac{7}{9}<\frac{1}{9}<\frac{3}{9}$
• B. $\frac{1}{9}<\frac{3}{9}<\frac{4}{9}<\frac{7}{9}$
• C. $\frac{4}{9}<\frac{3}{9}<\frac{1}{9}<\frac{7}{9}$
• D. $\frac{7}{9}<\frac{4}{9}<\frac{3}{9}<\frac{1}{9}$

Answer 1

The correct option is B

$\frac{1}{9}<\frac{3}{9}<\frac{4}{9}<\frac{7}{9}$

The given fractions are like fractions because all of them have the same denominator, which is 9.

To arrange the following fractions in ascending order we need to arrange their numerators in ascending order.

1 < 3 < 4 < 7

$\therefore \frac{1}{9}<\frac{3}{9}<\frac{4}{9}<\frac{7}{9}$.