Question

On billion electrons pass from point P towards another point Q in 10^-3 s . What is the current in ampere? What is its direction?

Answer 1

$$\begin{gathered} I=\frac{ne}{t} \\ I=\frac{{10}^6\times 1.6\times {10}^{-19}}{{10}^{-3}}=1.6\times {10}^{-10}A \end{gathered}$$

Direction of current from point Q to point p i.e. opposite to the flow of electrons.