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Question

On bringing a lighted matchstick near the mouth of the test tube in which NaOHandZn react:


A

the matchstick gets extinguished

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B

the matchstick burns faster

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C

a pop sound is heard

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D

no effect is observed on the matchstick

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Solution

The correct option is C

a pop sound is heard


The explanation for the correct option:

Option C is the correct option.

  1. When one mole of zinc reacts with two moles of Sodium hydroxide NaOH it fives Sodium zincate Na2ZnO2, with Hydrogen H2 gas.
  2. The reaction of Zinc with Sodium hydroxide gives Sodium zincate and hydrogen gas is evolved.

ZnsZinc+2NaOHaqSodiumhydroxideNa2ZnO2sSodiumzincate+H2gHydrogengas

3. The hydrogen gas starts released from the vessel.

4. Therefore, if we bring a lighted matchstick near the vessel it burns with a pop sound.

5. It burns with a pop sound because hydrogen has the characteristics property to burn with a pop sound.

Explanation of incorrect options:

Option A:

  1. The matchstick does not get extinguished because the ignition temperature of the matchstick is near about 230°C and the room temperature is less than the ignition temperature.

Option B:

  1. Only the head of the matchstick burns faster because this head is made of Potassium chlorate KClO3 and it releases a lot of Oxygen when it burns.
  2. And due to this, the head burns faster but the rest of the body burns slowly.

Option D:

  1. A pop sound and the blue flame are observed on the matchstick because of burning the Hydrogen gas.

Final Answer: When Zinc reacts with Sodium hydroxide, a pop sound is heard.


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