We have,
(i) 3x + 2y = 5 3x + 2y – 5 = 0 and 2x – 3 y = 7 2x – 3y – 7 = 0
a1a2 = 32, b1b2= 2−3 & c1c2 = 57
Here, a1a2 ≠ b1b2
Therefore, the given pair of linear equations is consistent.
(ii) 2x – 3 y = 8 Þ 2x – 3 y – 8 = 0 and 4x – 6 y = 9 Þ 4x – 6 y – 9 = 0
a1a2 = 24 = 12 , b1b2= −3−6 = 12 & c1c2 = −8−9
Here, a1a2= b1b2≠ c1c2
Hence, the given pair is inconsistent