The correct option is D Intersect at a point
The equations are
⇒2x−y−3=0
⇒a1=2,b1=−1,c1=−3
⇒4x−y−5=0
⇒a2=4,b2=−1,c2=−5
Comparinga1a2,b1b2andc1c2
a1a2=24=12
b1b2=−1−1=11
⇒a1a2≠b1b2
hence, the given pair of equations has a unique solution therefore the pair of lines intersect at a point.